Thursday, April 24, 2008

Clinton has the popular vote

It seems that Obama is making the case that he has the popular vote. In order to do that you need to count everybody that is part of the voting process, including voters in Michigan and Flordia, two large states.

Looks like Clinton does have the popular vote according to the WSJ:

That means Sen. Obama retains his lead in the national delegate count with 1,723 to Sen. Clinton's 1,592, according to the Associated Press calculation, which includes superdelegate votes. But the Pennsylvania balloting narrowed the Illinois senator's margin to 131 delegate votes, with 408 pledged-delegate votes at stake in the remaining nine contests.In an analysis of the popular vote, the political Web site calculated that Sen. Obama now leads Sen. Clinton 14.4 million votes to 13.9 million. The gap both narrows and widens depending on how the popular vote is counted, though.

The RealClearPolitics total doesn't include 1.2 million votes cast by Florida and Michigan voters. Both states lost their seats at the national convention this summer in Denver as punishment for holding their primaries out of turn, but are certain to get back at least some votes, the Democratic Party has said.

Sen. Obama took his name off the Michigan ballot, so he got no votes there. But Sen. Clinton remained on the ballot, and the New York senator picked up 329,000 votes. Both candidates were on the ballot in Florida, which Sen. Clinton won by about 300,000 votes. If those two states' disputed votes are counted, Sen. Clinton would lead in the popular vote by 123,000.

The RealClearPolitics estimate also doesn't include the results of four caucus states that didn't release numbers. The Web site calculates that Sen. Obama would net 110,000 votes if its estimate of those vote totals were included. That would still leave him behind by 13,000 votes, or 0.04%, of the 30.7 million cast.'

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